![If `log2, log(2x-1) and log(2x+3)` are in A.P., then the value of x is (A) 5/2 (C) log,5 (B) ... - YouTube If `log2, log(2x-1) and log(2x+3)` are in A.P., then the value of x is (A) 5/2 (C) log,5 (B) ... - YouTube](https://i.ytimg.com/vi/oKI2mreTRpo/maxresdefault.jpg)
If `log2, log(2x-1) and log(2x+3)` are in A.P., then the value of x is (A) 5/2 (C) log,5 (B) ... - YouTube
![Solve log [Base(2x+3)] {6square(x) + 23x + 21} = 4 - log [Base(3x+7)] {4square(x) + 12x + 9} - YouTube Solve log [Base(2x+3)] {6square(x) + 23x + 21} = 4 - log [Base(3x+7)] {4square(x) + 12x + 9} - YouTube](https://i.ytimg.com/vi/DYRjdieydPc/maxresdefault.jpg)
Solve log [Base(2x+3)] {6square(x) + 23x + 21} = 4 - log [Base(3x+7)] {4square(x) + 12x + 9} - YouTube
![How to solve for x in this equation log base 3 (x^2 + x - 6) = log base 3 (x ^2 + 7x + 12) - 2/3log base 9 (8) - Quora How to solve for x in this equation log base 3 (x^2 + x - 6) = log base 3 (x ^2 + 7x + 12) - 2/3log base 9 (8) - Quora](https://qph.fs.quoracdn.net/main-qimg-92b2cdeba8dbe90bce9405c7d3901ace.webp)
How to solve for x in this equation log base 3 (x^2 + x - 6) = log base 3 (x ^2 + 7x + 12) - 2/3log base 9 (8) - Quora
![1) Solve: log 27 x=-2/3 2) Write in logarithmic form: 49 1/2 = 7 3) Graph y = -2(3) -x 1)x= 27 -2/3 x = 2) ½ = log ) = -2(1/3) x. - ppt download 1) Solve: log 27 x=-2/3 2) Write in logarithmic form: 49 1/2 = 7 3) Graph y = -2(3) -x 1)x= 27 -2/3 x = 2) ½ = log ) = -2(1/3) x. - ppt download](https://images.slideplayer.com/13/3934825/slides/slide_4.jpg)
1) Solve: log 27 x=-2/3 2) Write in logarithmic form: 49 1/2 = 7 3) Graph y = -2(3) -x 1)x= 27 -2/3 x = 2) ½ = log ) = -2(1/3) x. - ppt download
![IF log 2 log 2 to the power x 1 and log 2x 3 are in AP Find x - Mathematics - TopperLearning.com | sqk90tff IF log 2 log 2 to the power x 1 and log 2x 3 are in AP Find x - Mathematics - TopperLearning.com | sqk90tff](https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=dd9f9be39888bc51e0628640bbfa9469.png)
IF log 2 log 2 to the power x 1 and log 2x 3 are in AP Find x - Mathematics - TopperLearning.com | sqk90tff
![if $\sqrt{\log_4(\log_3(\log_2(x^2-2x+a)))}$ is defined for all x={set of real numbers} then find the valid interval for "a". - Mathematics Stack Exchange if $\sqrt{\log_4(\log_3(\log_2(x^2-2x+a)))}$ is defined for all x={set of real numbers} then find the valid interval for "a". - Mathematics Stack Exchange](https://i.stack.imgur.com/afm79.jpg)
if $\sqrt{\log_4(\log_3(\log_2(x^2-2x+a)))}$ is defined for all x={set of real numbers} then find the valid interval for "a". - Mathematics Stack Exchange
![log2 (9 - 2X) = 10log (3-x) Solve for x.a)0b)3c)Both (a) and (b)d)0 and 6Correct answer is option 'A'. Can you explain this answer? | EduRev Quant Question log2 (9 - 2X) = 10log (3-x) Solve for x.a)0b)3c)Both (a) and (b)d)0 and 6Correct answer is option 'A'. Can you explain this answer? | EduRev Quant Question](https://cdn3.edurev.in/ApplicationImages/Temp/695075_686c87bc-a4bb-47e6-b448-bb23730e7e8c_lg.png)