![Definite Integration integration class 12 | 0 to pi/2 log(tanx) | NCERT solutions | Exams 2020 AVTE - YouTube Definite Integration integration class 12 | 0 to pi/2 log(tanx) | NCERT solutions | Exams 2020 AVTE - YouTube](https://i.ytimg.com/vi/mHD_iNb4T3c/maxresdefault.jpg)
Definite Integration integration class 12 | 0 to pi/2 log(tanx) | NCERT solutions | Exams 2020 AVTE - YouTube
![Finding integral $\int_{0}^{\infty} \frac{x^{\alpha}\log{x}}{1-x^2}dx$ using complex analysis - residues - Mathematics Stack Exchange Finding integral $\int_{0}^{\infty} \frac{x^{\alpha}\log{x}}{1-x^2}dx$ using complex analysis - residues - Mathematics Stack Exchange](https://i.stack.imgur.com/nvMCp.jpg)
Finding integral $\int_{0}^{\infty} \frac{x^{\alpha}\log{x}}{1-x^2}dx$ using complex analysis - residues - Mathematics Stack Exchange
![Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2` - YouTube Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2` - YouTube](https://i.ytimg.com/vi/4XEd1-Lq8Qg/maxresdefault.jpg)
Prove that: `int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2` - YouTube
![Integral $\int_{-1}^1\frac1x\sqrt{\frac{1+x}{1 -x}}\ln\left(\frac{2\,x^2+2\,x+1}{2\,x^2-2\,x+1}\right) \mathrm dx$ - Mathematics Stack Exchange Integral $\int_{-1}^1\frac1x\sqrt{\frac{1+x}{1 -x}}\ln\left(\frac{2\,x^2+2\,x+1}{2\,x^2-2\,x+1}\right) \mathrm dx$ - Mathematics Stack Exchange](https://i.stack.imgur.com/ztodM.png)
Integral $\int_{-1}^1\frac1x\sqrt{\frac{1+x}{1 -x}}\ln\left(\frac{2\,x^2+2\,x+1}{2\,x^2-2\,x+1}\right) \mathrm dx$ - Mathematics Stack Exchange
![File:Max (Joint Log Likelihood per N) for Beta distribution Maxima at alpha=beta= 0.25,0.5,1,2,4,6,8 - J. Rodal.png - Wikimedia Commons File:Max (Joint Log Likelihood per N) for Beta distribution Maxima at alpha=beta= 0.25,0.5,1,2,4,6,8 - J. Rodal.png - Wikimedia Commons](https://upload.wikimedia.org/wikipedia/commons/1/1d/Max_%28Joint_Log_Likelihood_per_N%29_for_Beta_distribution_Maxima_at_alpha%3Dbeta%3D_0.25%2C0.5%2C1%2C2%2C4%2C6%2C8_-_J._Rodal.png)